**(a)**

Kinetic energy:

$\overline{){\mathbf{K}}{\mathbf{E}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{m}}{{\mathbf{v}}}^{{\mathbf{2}}}}$

v = 1.20 × 10^{4} km/hr (1hr/60min)(1min/60s)(1000m/1km) = 3.333 × 10^{3} m/s

KE = (1/2)(629)(3.333 × 10^{3}) = 3.49 × 10^{9} J

Ten days after it was launched toward Mars in December 1998, the Mars Climate Orbiter spacecraft (mass 629 kg) was 2.87x10^{6} km from the earth and traveling at 1.20x10^{4} km/hr relative to the earth.

(a) At this time, what was the spacecraft's kinetic energy relative to the earth?

(b) What was the potential energy of the earth-spacecraft system?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Universal Law of Gravitation concept. You can view video lessons to learn Universal Law of Gravitation. Or if you need more Universal Law of Gravitation practice, you can also practice Universal Law of Gravitation practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Licini's class at LEHIGH.